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H-atom is exposed to electromagnetic radiation of 1028 A and gives out induced radiations. Calculate the wavelenth of induced radiations. H-atom is exposed to electromagnetic radiation of 1028 A and gives out induced radiations. Calculate the wavelenth of induced radiations.
H-atom is exposed to UV radiation having wavelength 102.8nm the energy of photon corresponding to 102.8 nm waveegth is E = hc/λ = 1242 eV-nm /102.8 nm = 12.42 eV The energy needed to take athe H atom frm ground state to first excited state is E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV and to the second excited state is E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV and to the third excited state is E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV thus 12.42 eV photon has large probability of being absorbed in 12.1 eV The corresponding waveegth is: λ = 1242/12.1 =103 nm --- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch
H-atom is exposed to UV radiation having wavelength 102.8nm
the energy of photon corresponding to 102.8 nm waveegth is
E = hc/λ = 1242 eV-nm /102.8 nm
= 12.42 eV
The energy needed to take athe H atom frm ground state to first excited state is
E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV
and to the second excited state is
E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV
and to the third excited state is
E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV
thus 12.42 eV photon has large probability of being absorbed in 12.1 eV
The corresponding waveegth is: λ = 1242/12.1
=103 nm
---
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch
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