if 1 mole of pb(n3)2 is changed to pbo and no , then moles of electrons lost are

a 10 b 8

c 14 d 16

To determine how many moles of electrons are lost when 1 mole of lead(II) azide, Pb(N3)2, is converted to lead(II) oxide, PbO, and nitrogen monoxide, NO, we need to analyze the oxidation states of the elements involved in the reaction.

Understanding the Reaction

First, let’s break down the compounds:

• Pb(N3)2: In this compound, lead (Pb) has an oxidation state of +2, while each azide ion (N3) carries a -1 charge. Therefore, the overall charge balances out to zero.
• PbO: In lead(II) oxide, lead again has an oxidation state of +2, and oxygen (O) has an oxidation state of -2.
• NO: In nitrogen monoxide, nitrogen (N) has an oxidation state of +2, while oxygen remains at -2.

Oxidation and Reduction

In this reaction, lead is not changing its oxidation state; it remains +2 in both Pb(N3)2 and PbO. However, the nitrogen in Pb(N3)2 is changing from an oxidation state of -1 in the azide ion to +2 in nitrogen monoxide (NO). This change indicates that nitrogen is being oxidized.

Calculating the Change in Electrons

To find out how many electrons are lost by nitrogen during this conversion, we can look at the change in oxidation states:

• Each nitrogen in the azide ion (N3) starts at -1 and goes to +2 in NO.
• The change in oxidation state for each nitrogen atom is from -1 to +2, which is a change of +3.

Since there are three nitrogen atoms in the azide ion, the total change in oxidation state for all nitrogen atoms is:

• 3 nitrogen atoms × 3 (change per atom) = 9 electrons lost.

Final Consideration

However, we also need to consider that the azide ion is converted to nitrogen monoxide, which means that for every mole of Pb(N3)2, we are producing 2 moles of NO. Therefore, the total number of moles of electrons lost in the entire reaction is:

• 9 electrons lost (from 3 nitrogen atoms) × 2 (for 2 moles of NO) = 18 electrons lost.

Since the question asks for the moles of electrons lost, we can summarize that the correct answer is not listed among the options provided. However, if we consider the closest answer based on the calculations, it seems there might be a misunderstanding in the options given.

In conclusion, based on the oxidation states and the changes occurring in the reaction, the total moles of electrons lost when converting 1 mole of Pb(N3)2 to PbO and NO is 18. If you have any further questions or need clarification on any part of this process, feel free to ask!