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two flask of equal voliume connected by a narrow tube (of negligible volume) are at 27C and contains 0.7 moles of H2 at 0.5 atm .one of the flask is then immersed in a bath kept at 127C while the other reains at 27C .calculate the final pressure and the number of moles of H2 in each flask
PV=nRT
0.5v=0.7R300
so v=420R
In 2nd case the pressure will be same in both flasks and sum of moles of gas will be 0.7
Flask 1-
PV=aRT
P420R=aR300
a=1.4P
Flask2-
PV=bRT
P420R=bR400
b=1.05P
a + b = 2.45P = 0.7
P = 0.28
a= 0.294, b= 0.392
why did u take volume of both the flasks in case2 same..?
i mean if the volume of two flasks together is 420R, the the volume of 1 flask shud have been 210.
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