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two flask of equal voliume connected by a narrow tube (of negligible volume) are at 27C and contains 0.7 moles of H2 at 0.5 atm .one of the flask is then immersed in a bath kept at 127C while the other reains at 27C .calculate the final pressure and the number of moles of H2 in each flask

two flask of equal voliume connected by a narrow tube (of negligible volume) are at 27C and contains 0.7 moles of H2 at 0.5 atm .one of the flask is then immersed in a bath kept at 127C while the other reains at 27C .calculate the final pressure and the number of moles of H2 in each flask   

Grade:

4 Answers

saurabh av
15 Points
10 years ago

PV=nRT

0.5v=0.7R300

so v=420R

 

In 2nd case the pressure will be same in both flasks and sum of moles of gas will be 0.7

Flask 1-

PV=aRT

P420R=aR300

a=1.4P

 

Flask2-

PV=bRT

P420R=bR400

b=1.05P

 

a + b = 2.45P = 0.7

P = 0.28

a= 0.294, b= 0.392

meetakshi behal
18 Points
9 years ago

why did u take volume of both the flasks in case2 same..?

i mean if the volume of two flasks together is 420R, the the volume of 1 flask shud have been 210.

Aadi
19 Points
5 years ago
The volumes does not depict volume of container but gas.In expression PV=nRT V is volume of gas taken.Thus taking 420R in this case is valid.
 
 
 
ankit singh
askIITians Faculty 614 Points
one year ago
Two flasks of equal volume connected by a narrow tube (of negligible volume) are at 27C and contain 0.70 mole of H2 to 0.5atm One of the flask is then immersed into a bath kept at 127∘C while the other remains at 27C Calculate the final pressure and the number of mole of H2 in each flask .

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