Pramod J AskiitiansExpert-IIT-B
Last Activity: 13 Years ago
Dear student,
number of chlorine atoms in ccl4 = 4
number of moles of ccl4 = 10^25/(4*6.623*10^23) = 3.775 moles
weight of 3.775 moles = 3.775*[12+4*35] = 573.8
volume required = 573.8/1.5 =382.33 litres
i hope this clears :)