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what time will be required for a current of 0.1A to deposit all copper from 50dmcube of 0.1N solution?

satyaprakash singh , 13 Years ago
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bhanu p

Last Activity: 13 Years ago

we know that , N = W/E  => E = W/N  also , we have Z = E/96500  substituting this in faradays first law ,-

W = ZIt => W = EIt/96500 = WIt/N(96500)  => W = W(0.1)t/0.1(96500) => t = 96500(50) = 482500s

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