Hi

Ans 1:

For silver , the conversion is Ag⁺ + e^- -> Ag

Therefore 1 mole of electrons are reqd to make 1 mole i.e 108 gm of silver. hence .2 moles of electron will make .2x108 = 21.6 gm of silver.

For zinc, the connversion is Zn²⁺ + 2e^- -> Zn

Therefore 2 moles of elctrons are reqd to make 1 mole i.e 65 gm of zinc, hence .2 mole electrons shall make .2x65/2 = 6.5 gm of zinc.

Hi

Ans 2:

For a steady flow, the current I in amperes can be calculated with the following equation:

where

Q is the electric charge in coulombs transferred

t is the time in seconds

More generally, electric current can be represented as the time rate of change of charge, or

.

therefore, Q= 30 A x 70.2 x 60 sec = 126360 coulombs

1 faraday = 96 485.3415 coulombs

Therefore answer is 126360/96485.3415 = 1.31 faraday

Hi

Please repost the third question, the question is not clear.

1)       for silver deposition :       Ag⁺     +     e^-             ------>   Ag

                                                                     1 mole                   1 mole

         so , 0.2 moles of Ag is deposited i.e., 0.2*108 = 21.6 grams

        for zinc deposition :   Zn²⁺     +   2e^-                ------>    Zn

                                                              2 mole                       1 mole

        so , 0.1 moles of Zn is deposited i.e., 0.1*65 =  6.5 grams

        So option is C

2)   Electric current is the rate of charge flow past a given point in an electric circuit, measured in Coulombs/second which is named Amperes

     so Q = i*t

       Q=30*70.2*60

     Q = 126360 Coulombs

    but 1 faraday = 96485 Coulombs

    So its Q = 1.31 faraday

    So option is C

3) I want to make a small correction to question reg. elecric potential of  cu²⁺/cu⁺ ( taken frm standard books )

Its cu²⁺/cu⁺ =0.153V  i.e.,                     cu²⁺ + e^-   ------>  cu⁺            E0 = 0.153 V

Now going into problem:  Cu+ solutions, tend to give a disproportion reaction:

                                                       2Cu⁺ ----- >   Cu + Cu²⁺

                      
                     cu⁺ + e-    ------>  cu                                E0 = 0.53 V        so,  nE⁰ = 0.53 V   

                     cu⁺            ------>  cu²⁺ + e^-               E0 = - 0.153 V       so,   nE⁰ = - 0.153 V

on adding above rxns we get  
 2Cu⁺ ----- >   Cu + Cu²⁺                  with  E⁰ = +0.377 V