Hi
Ans 1: 
For silver , the conversion is Ag+ + e- -> Ag
Therefore 1 mole of electrons are reqd to make 1 mole i.e 108 gm of silver. hence .2 moles of electron will make .2x108 = 21.6 gm of silver.
 
For zinc, the connversion is Zn2+ + 2e- -> Zn
Therefore 2 moles of elctrons are reqd to make 1 mole i.e 65 gm of zinc, hence .2 mole electrons shall make .2x65/2 = 6.5 gm of zinc.
						

							
Hi
Ans 2:
For a steady flow, the current I in amperes can be calculated with the following equation:
 
where
Q is the electric charge in coulombs transferred 
t is the time in seconds 
More generally, electric current can be represented as the time rate of change of charge, or
. 
therefore, Q= 30 A x 70.2 x 60 sec = 126360 coulombs
1 faraday = 96 485.3415 coulombs
 
Therefore answer is 126360/96485.3415 = 1.31 faraday
						

							
Hi
Please repost the third question, the question is not clear.
						

							
1)       for silver deposition :       Ag+     +     e-             ------>   Ag
                                                                     1 mole                   1 mole
         so , 0.2 moles of Ag is deposited i.e., 0.2*108 = 21.6 grams
        
         for zinc deposition :   Zn2+     +   2e-                ------>    Zn
                                                              2 mole                       1 mole
        so , 0.1 moles of Zn is deposited i.e., 0.1*65 =  6.5 grams
        So option is C
 
2)   Electric current is the rate of charge flow past a given point in an electric circuit, measured in Coulombs/second which is named Amperes
     so Q = i*t
       Q=30*70.2*60
     Q = 126360 Coulombs
    but 1 faraday = 96485 Coulombs
    So its Q = 1.31 faraday
    So option is C
 
 
3) I want to make a small correction to question reg. elecric potential of  cu2+/cu+ ( taken frm standard books )



Its cu2+/cu+ =0.153V  i.e.,                     cu2+ + e-   ------>  cu+            E0 = 0.153 V



Now going into problem:  Cu+ solutions, tend to give a disproportion reaction:



                                                       2Cu+ ----- >   Cu + Cu2+



                       

                     cu+ + e-    ------>  cu                                E0 = 0.53 V        so,  nE0 = 0.53 V    



                     cu+            ------>  cu2+ + e-               E0 = - 0.153 V       so,   nE0 = - 0.153 V 



on adding above rxns we get   

 2Cu+ ----- >   Cu + Cu2+                  with  E0 = +0.377 V