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(NCH3)3 IS PYRAMIDAL UT N(SiH3)3 IS TRIANGULAR.EXPLAIN

(NCH3)3 IS PYRAMIDAL UT N(SiH3)3 IS TRIANGULAR.EXPLAIN

Grade:12

4 Answers

PRIYANKA TATA ASKIITIAN
78 Points
11 years ago

Hi Shivam,

(CH3)3N has sp3 hybridization on nitrogen with pyramidal shape due to p∏-p∏ bonding...whereas in (SiH3)3N Si has vacant d orbitals which provides p∏-d∏ bonding and so nitrogen has sp2 hybridization with trigonal planar shape..!

Priyanka tata

vikas askiitian expert
509 Points
11 years ago

here the reason is Ppi - dpi back bonding due to this it becomes planer but in (NCH3)3 there

is no such bonding possible...

Akash rastogi
15 Points
3 years ago
Because the
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the answer to your problem attached herewith.
 
N(CH3)3 has sp3 hybridization on nitrogen with pyramidal shape due to pπ-pπ bonding...whereas in N(SiH3)3 Si has vacant d orbitals which provides pπ-dπ bonding and so nitrogen has sp2 hybridization with trigonal planar shape.
 
Hope it helps
Thanks and regards,
Kushagra

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