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(NCH3)3 IS PYRAMIDAL UT N(SiH3)3 IS TRIANGULAR.EXPLAIN

SHIVAM JAIN , 14 Years ago
Grade 12
anser 4 Answers
PRIYANKA TATA ASKIITIAN

Last Activity: 14 Years ago

Hi Shivam,

(CH3)3N has sp3 hybridization on nitrogen with pyramidal shape due to p∏-p∏ bonding...whereas in (SiH3)3N Si has vacant d orbitals which provides p∏-d∏ bonding and so nitrogen has sp2 hybridization with trigonal planar shape..!

Priyanka tata

Approved
vikas askiitian expert

Last Activity: 14 Years ago

here the reason is Ppi - dpi back bonding due to this it becomes planer but in (NCH3)3 there

is no such bonding possible...

Approved
Akash rastogi

Last Activity: 7 Years ago

Because the
Kushagra Madhukar

Last Activity: 5 Years ago

Dear student,
Please find the answer to your problem attached herewith.
 
N(CH3)3 has sp3 hybridization on nitrogen with pyramidal shape due to pπ-pπ bonding...whereas in N(SiH3)3 Si has vacant d orbitals which provides pπ-dπ bonding and so nitrogen has sp2 hybridization with trigonal planar shape.
 
Hope it helps
Thanks and regards,
Kushagra
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