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how many litres of detonating gas will be produced at ntp in the decomposition of 0.1 mole of waterby an electric current?
Dear student,
Use the T and P conditions of NTP...
AT STP AND NTP
n(MOLES)=V(LITRES)/22.4
ACCORDING TO GIVEN INFORMATION n=0.1 V=?
0.1 X 22.4=V
V=2.24LITRES........................ANSWER
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