Grade 12Physical Chemistry
Potassium ferrocyanide is 50% ionized in aqueous
solution, its van't Hoff factor will be equal to ——.
Potassium ferrocyanide is 50% ionized in aqueous
solution, its van't Hoff factor will be equal to ——.
2 Answers
vikas askiitian expert
Approved Tutor Answer15 Years agoK4[Fe(CN)6]•3H2O => 4K+ + [Fe(CN)6]4-
1 0 0 (initial)
1-x 4x x (atfter dissociation)
vant hoff factor (i) = moles after dissotion/total initial moles
= 1+4x
50% ionise means x = 0.5 so
i = 1 + 4*0.5 = 3
its vant hoff factor is 3
Yash Chourasiya
Hello Student
K4[Fe(CN)6].3H2O→ 4K++ [Fe(CN)6]4-
1 0 0 (initial)
(1-x) 4x x (atfter dissociation)
vant hoff factor (i) = moles after dissotion/total initial moles
= 1+4x
50% ionise means x = 0.5
so, i = 1 + 4*0.5 = 3
Vant hoff factor is 3
I hope this answer will help you.
K4[Fe(CN)6].3H2O→ 4K++ [Fe(CN)6]4-
1 0 0 (initial)
(1-x) 4x x (atfter dissociation)
vant hoff factor (i) = moles after dissotion/total initial moles
= 1+4x
50% ionise means x = 0.5
so, i = 1 + 4*0.5 = 3
Vant hoff factor is 3
I hope this answer will help you.
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