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He atom can be excited to 1s1 2p1 by wavelength 58.44 nm. If lowest excited state for He lies 4857cm-1 below the above. Calculate the energy for the lower excitation state.


8 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

You know the wavelength and wave number. Calculate the energy using simple direct formuka.

It comes out to be 3.3*10^(-18) J

8 years ago
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