A 0.1 molar solution of week base BOH is 1% dissociated. If 0.2 moles of bcl is added in 1 liter solution of BOH,the degree of dissociation of BOH will become (1){2}{10^-3} (2){5}{10^-5} (3)00.5 (4)0.02

Praveen Kumar beniwal Grade:

        A 0.1 molar solution of week base BOH is 1% dissociated. If 0.2 moles of bcl is added in 1 liter solution of BOH,the degree of dissociation of BOH will become

(1){2}{10^-3}

(2){5}{10^-5} 

(3)00.5

(4)0.02

8 years ago

Answers : (2)

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vikas askiitian expert

509 Points

							alfa(degree of dissotion) = (K_b/c)
1% means alfa = 0.01 , c = 0.1 so
K_b = 10^-5                          .......................1(K_b is constant )
 
K_b = [B⁺][0H^-]/[BOH]
finally 0.2mol of BCl is added so
B⁺ from BCl is added in the solution & here common ion effect is produced ...
now , K_b = [BCl][OH^-]/[BOH]
OH^- = C(alfa)                              (alfa is final degree of dissociation)
BOH = C
k_b = [BCl]alfa
10^-5 = 0.2(alfa)
alfa = 5 * 10^-5
option b) is correct

8 years ago

Approved

View Solution

vikas askiitian expert

509 Points

							alfa(degree of dissotion) = (K_b/c)
1% means alfa = 0.01 , c = 0.1 so
K_b = 10^-5                          .......................1(K_b is constant )
 
K_b = [B⁺][0H^-]/[BOH]
finally 0.2mol of BCl is added so
B⁺ from BCl is added in the solution & here common ion effect is produced ...
now , K_b = [BCl][OH^-]/[BOH]
OH^- = C(alfa)                              (alfa is final degree of dissociation)
BOH = C
k_b = [BCl]alfa
10^-5 = 0.2(alfa)
alfa = 5 * 10^-5
option b) is correct
 
approve my ans if u like