A 0.1 molar solution of week base BOH is 1% dissociated. If 0.2 moles of bcl is added in 1 liter solution of BOH,the degree of dissociation of BOH will become
(1){2}{10^-3}
(2){5}{10^-5}
(3)00.5
(4)0.02

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vikas askiitian expert · Answer

alfa(degree of dissotion) = (K b /c) 1% means alfa = 0.01 , c = 0.1 so K b = 10 -5 .......................1(K b is constant ) K b = [B + ][0H - ]/[BOH] finally 0.2mol of BCl is added so B + from BCl is added in the solution & here common ion effect is produced ... now , K b = [BCl][OH - ]/[BOH] OH - = C(alfa) (alfa is final degree of dissociation) BOH = C k b = [BCl]alfa 10 -5 = 0.2(alfa) alfa = 5 * 10 -5 option b) is correct

vikas askiitian expert · Answer

alfa(degree of dissotion) = (K b /c) 1% means alfa = 0.01 , c = 0.1 so K b = 10 -5 .......................1(K b is constant ) K b = [B + ][0H - ]/[BOH] finally 0.2mol of BCl is added so B + from BCl is added in the solution & here common ion effect is produced ... now , K b = [BCl][OH - ]/[BOH] OH - = C(alfa) (alfa is final degree of dissociation) BOH = C k b = [BCl]alfa 10 -5 = 0.2(alfa) alfa = 5 * 10 -5 option b) is correct approve my ans if u like

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A 0.1 molar solution of week base BOH is 1% dissociated. If 0.2 moles of bcl is added in 1 liter solution of BOH,the degree of dissociation of BOH will become (1){2}{10^-3} (2){5}{10^-5} (3)00.5 (4)0.02

A 0.1 molar solution of week base BOH is 1% dissociated. If 0.2 moles of bcl is added in 1 liter solution of BOH,the degree of dissociation of BOH will become
(1){2}{10^-3}
(2){5}{10^-5}
(3)00.5
(4)0.02

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