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What is de-Broglie wavelength of a He-atom in a container at 300K. (Use Uavg)
Ans. 0.79 angstrom
average speed of molecule (vavg)= (8RT/piM)1/2
M is molar mass = 4
T = temperature = 300k , R = 0.08321)
now use , lamda = h/mvavg , this will give u the ans 0.79 angstroms
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