calculate the number of next neighbours of Cs^+ in a lattice of cscl

the given lattice is of CsCl

We can see the following from the structure :

1. In this structure , the Cl^- ions are at the corners of a cube whereas the Cs⁺ ions are at the centre of the cube or vice versa.

2. This structure has an 8:8 coordination number , i.e each Cs⁺ ion is touching eight Cl^- ions and each Cl^- ion is touching 8 Cs⁺ ions.

so the number of next neighbours of Cs⁺ in CsCl = 8 (it is surrounded by 8 Cl^- ions)

Please approve !