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Grade: 12

                        

The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be??? Pls provide the exact answer someone...

9 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

lamda = h/mv

h = 6.6*10-34

m = 9.1*10-31

v = 2.2*106 m/s

lamda = 3.29*10-10m  = 3.3 angstromes unit

9 years ago
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