The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be???

Pls provide the exact answer someone...

Question

The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be??? Pls provide the exact answer someone...

vikas askiitian expert · Answer

lamda = h/mv h = 6.6*10 -34 m = 9.1*10 -31 v = 2.2*10 6 m/s lamda = 3.29*10 -10 m = 3.3 angstromes unit

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The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be??? Pls provide the exact answer someone...

The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be???

Pls provide the exact answer someone...

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The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be??? Pls provide the exact answer someone...

The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be??? Pls provide the exact answer someone...

1 Answers

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The velocity of an H-atom in ground state is 2.2*10^6 m/s.The de-broigle wavelength of the electron would be???

Pls provide the exact answer someone...