If excluded volume is taken zero compressibility factor z isa)1-a/RTVb)1+Pb/RTc)PV/RTd)RT/PV

If excluded volume is taken zero, Vander Wall's Equation becomes:

(P +  an²

(P +  a

Vander Wall's Equation (for 0 excluded volume) for 1 mole of an ideal gas:

(P + a/V

vander valls equation is

(p+a/v²)(v-b) = RT

if excluded volume is 0 then correction term in volume means 'b' is 0 ...

now , eq becomes

(p + a/v²)v = RT

pv + a/v = RT

pv/RT + a/vRT = 1

z + a/vRT = 1

z = 1 - a/vRT

option a is correct

Approved