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If the average life time of an excited state of H atom is of order 10-8 sec, estimate how many orbits an e- makes when it is in the state n=2 and before it suffers a transition to n=1 state
speed of electron in any orbit = vn = vo/n (vo = 2.18*106m/s) so , v2 = vo/2 = 1.09*106m/s radius of orbit = rn = aon2 (ao = 52.9 * 10-12m) so , r2 = 2.12*10-10m v = X/T x = @r so ( r is radius of second orbit) v = @r/T ( @ is angular displacement) @ = vT/r @ = 2pi(n) (here n is number of revolutions) 2pi(n) = vT/r .......................1 substituting values of v,r,T we get n = 8.18*106 revolutions approve if u like this ans
speed of electron in any orbit = vn = vo/n (vo = 2.18*106m/s)
so , v2 = vo/2 = 1.09*106m/s
radius of orbit = rn = aon2 (ao = 52.9 * 10-12m)
so , r2 = 2.12*10-10m
v = X/T
x = @r so ( r is radius of second orbit)
v = @r/T ( @ is angular displacement)
@ = vT/r
@ = 2pi(n) (here n is number of revolutions)
2pi(n) = vT/r .......................1
substituting values of v,r,T we get
n = 8.18*106 revolutions
approve if u like this ans
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