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The first ionisation energy of potassium is 100kcal mol-1.Calculate the lowest possible frequency of light that can ionise a potassium atom.
from bohrs theory , E = Eo(1-1/n2)
E1 (ionisation energy) = 100Kcalmol-1 = 4.2*105joulesmol-1
this E1 is for 1 mol , for 1 atom Eo will be E1/Na (Na = avagadro number)
Eo = E1/Na = 7*10-18 joules
so , E = Eo(1-1/n2)
E = hv (v is frequency of light emmited)
hv = 7*10-18 (1-1/n2)
h = 6.6*10-34 , n should be 2 for minimum frequency ...
hv = 7*10-18(1-1/4)
v = 7.95*1015 hertz
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