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How much energy is emitted out when a mole of electron falls in 1g atom of H from 2 to 1 orbit?(R h =109678 cm -1 )

How much energy is emitted out when a mole of electron falls in 1g atom of H from 2 to 1 orbit?(Rh=109678 cm-1)

Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Use 1/l=RZ2(1/n1^2-1/n^2)

E=hc/l

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

vikas askiitian expert
509 Points
13 years ago

E = 13.6 (1-1/n2)       

this is the energy librated when 1 electron falls from n=n to n=1

 

for 1 mol of electrons or  Na number of electrons energy will be

ET = 13.6 Na(1-1/n2)

n = 2      (given)

Na = 6 * 1023

 

ET = 13.6*(3/4)*6*1023

ET = 6.12*1024 ev

1 ev = 1.6*10-19 J so

ET = 9.8*105 J or 980  KJ

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