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two closed vessels A & B of equal volume containing air pressure P 1 and temprature T 1 ARE CONNECTED TO EACH OTHER THROUGH THE NARROW OPEN TUBE. IF THE OF ONE IS NOW MAINTAINED AT T1 AND OTHER AT T2 WHERE T1 > T2 , THEN WHAT WILL BE THE FINAL PRESSURE ? ans=2p1t2/ti+t2 what is its explanation?
acc. to ideal gas eqn: PV=NRT & it is given that volume is constant means same in both vessels. hence, temp. is directly proprotional to pressure. as T1>T2 so P1 will also be greater than P2. that is P1>P2, this is the explanation of your answer..........
acc. to ideal gas eqn:
PV=NRT
& it is given that volume is constant means same in both vessels. hence, temp. is directly proprotional to pressure.
as T1>T2 so P1 will also be greater than P2.
that is P1>P2, this is the explanation of your answer..........
PV=NRT& it is given that volume is constant means same in both vessels. hence, temp. is directly proprotional to pressure.n1 + n2 = n3 + n4 (n1 ,n2 = initial n3 , n4= final )(Po/To) +( Po/To) = (P/To) + (P/T)Now solve this simple equation....wherePo= initial pressureTo= initial temperatureP = final pressureT = final temperature
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