7 MOLES OF TETRA ATOMIC NON LINEAR GAS AAT 10 ATM AND T K ARE MIXED WITH 6 MOLES OF ANOTHER GAS B AT T/3 K AND 5 ATM IN A CLOSED RIGID VESSELWITHOUT ENERGY TRANSFER WITH SORROUNDINGSIF THE FINAL TEMPRATURE OF THE MIXTURE WAS 5T/6 K , THEN GAS B IS?DIATOMIC OR TRIATOMIC ?
Sumeet Garg , 13 Years ago
Grade 11
1 Answers
Siledar Divakar
Last Activity: 7 Years ago
Cv of gas A = 3/2 R + 3/2 R + 6R = 9R
Let Cv of gas B = Cv
Heat lost by gas A = 7 x 9R (T- 5T/6)
Heat gained by gas B = 6 Cv (5T/6 – T/3)
63 R(T/6) = 6 Cv (T/2)
Cv=7 R/2
therefore, gas is diatomic = 3R/2 + R + R = 7 R/2
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free