A CERTAIN HYDRATE HAS THE FORMULA MGSO4.XH2O.A QUANTITY OF 54.2g OF COMPOUND IS HEATED IN AN OVEN TO DRIVE OF THE WATER.IF THE STEAM GENERATED EXERTS THE PRESSURE OF 24.8ATM INA 2.0 L CONTAINER AT 120 C CALCULATE X ?

Dear student,

P=24.8 bar

V = 2l = 0.002 m^3

T = 120 = 393K

PV = mRT/M => m = PVM/RT

=> m = 24.8*10^5*2*10^-3*18/8.314*10^3*393 =0.02732 kg = 27.32g

percent weight of water in the compound = (27.32/54.2)*100 = 50.4

molecular weight of compound = 24+32+64+x*18

=> 120+18x = 0.504*18x => x = 13.33 since x is natural number x is approximated to 13

hope this explains.