A CERTAIN HYDRATE HAS THE FORMULAMGSO4.XH2O.A QUANTITY OF 54.2g OF COMPOUND IS HEATED IN AN OVEN TO DRIVE OF THE WATER.IF THE STEAM GENERATED EXERTS THE PRESSURE OF 24.8ATM INA 2.0 L CONTAINER AT 120 C CALCULATE X ?

Dear student,

P=24.8 bar

V = 2l = 0.002 m^3

T = 120 = 393K

PV = mRT/M => m = PVM/RT

=> m = 24.8*10^5*2*10^-3*18/8.314*10^3*393 =0.02732 kg = 27.32g

percent weight of water in the compound = (27.32/54.2)*100 = 50.4

molecular weight of compound = 24+32+64+x*18

=> 120+18x = 0.504*18x => x = 13.33 since x is natural number x is approximated to 13

hope this explains.