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Dear student,
P=24.8 bar
V = 2l = 0.002 m^3
T = 120 = 393K
PV = mRT/M => m = PVM/RT
=> m = 24.8*10^5*2*10^-3*18/8.314*10^3*393 =0.02732 kg = 27.32g
percent weight of water in the compound = (27.32/54.2)*100 = 50.4
molecular weight of compound = 24+32+64+x*18
=> 120+18x = 0.504*18x => x = 13.33 since x is natural number x is approximated to 13
hope this explains.
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