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How to find n-factor for disproportionation reaction?? what is the n-factor for this reaction Br2 + 2NaOH -> NaOBr + NaBr + H20
Dear Student you can calculate n factor in disproportionation reaction by the formula 1/N=1/n1 +1/n2 where n1=n factor for oxidation half n2=n factor for reduction half
Dear Student
you can calculate n factor in disproportionation reaction by the formula
1/N=1/n1 +1/n2
where n1=n factor for oxidation half
n2=n factor for reduction half
please prove the formula used in disproportionation reaction
First of all balance the reaction and then apply the fomula1/nf = 1/nf(red) + 1/nf(ox)so 1/nf = 1/2+1/10= 5/3
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