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Grade: 11
        

At what temperature will the total K.E of 0.3 mol of He be the same as the total K.E of 0.4 mol of Ar at 400K:


a) 533K


b) 400K


c) 346K


d) 300K

7 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

Solve this using this hint:

et u be the average or root-mean-square speed of a gas whose molar mass is M. Since N is the Avogadro's number, the average kinetic energy is (1/2) (M/N) u2 or

          M        3R T     3
K.E. = --- u2 = ---- = --- k T
2 N 2 N 2

Sagar Singh
B.Tech IIT Delhi
7 years ago
vikas askiitian expert
509 Points
							

KE = 3nRT/2

(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)

1 = (0.3)T/(0.4)(400)

 T = 400*4/3

    =533K

approve my ans if u like it

7 years ago
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