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At what temperature will the total K.E of 0.3 mol of He be the same as the total K.E of 0.4 mol of Ar at 400K:
a) 533K
b) 400K
c) 346K
d) 300K
Dear student,
Solve this using this hint:
et u be the average or root-mean-square speed of a gas whose molar mass is M. Since N is the Avogadro's number, the average kinetic energy is (1/2) (M/N) u2 or
M 3R T 3 K.E. = --- u2 = ---- = --- k T 2 N 2 N 2Sagar SinghB.Tech IIT Delhi
KE = 3nRT/2
(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)
1 = (0.3)T/(0.4)(400)
T = 400*4/3
=533K
approve my ans if u like it
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