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At what temperature will the total K.E of 0.3 mol of He be the same as the total K.E of 0.4 mol of Ar at 400K: a) 533K b) 400K c) 346K d) 300K

At what temperature will the total K.E of 0.3 mol of He be the same as the total K.E of 0.4 mol of Ar at 400K:


a) 533K


b) 400K


c) 346K


d) 300K

Grade:11

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
11 years ago

Dear student,

Solve this using this hint:

et u be the average or root-mean-square speed of a gas whose molar mass is M. Since N is the Avogadro's number, the average kinetic energy is (1/2) (M/N) u2 or

          M        3R T     3
K.E. = --- u2 = ---- = --- k T
2 N 2 N 2

Sagar Singh
B.Tech IIT Delhi
vikas askiitian expert
509 Points
11 years ago

KE = 3nRT/2

(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)

1 = (0.3)T/(0.4)(400)

 T = 400*4/3

    =533K

approve my ans if u like it

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