What volume of 0.40 M NH 3 solution must be added to 1Lof 0.1 m NH 4 Cl solution to give a buffer having pH of 10?For NH 3 , K B =1.8^10 -5 .

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vikas askiitian expert · Answer

[H + ] = 10 -10 [OH - ] = K w /H + = 10 -4 moles of NH 4 Cl = 0.1*1=0.1 for V Litre of NH 3 ,moles of NH 3 = 0.4*V now , K b = [salt][OH - ]/[base] 1.8*10 -5 = (moles of salt )*10 -4 /(moles of base) moles of base(NH 3 ) = 10/1.8*4=1.38L

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What volume of 0.40 M NH 3 solution must be added to 1Lof 0.1 m NH 4 Cl solution to give a buffer having pH of 10?For NH 3 , K B =1.8^10 -5 .

What volume of 0.40 M NH₃ solution must be added to 1Lof 0.1 m NH₄Cl solution to give a buffer having pH of 10?For NH₃, K_B=1.8^10^-5.

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What volume of 0.40 M NH 3 solution must be added to 1Lof 0.1 m NH 4 Cl solution to give a buffer having pH of 10?For NH 3 , K B =1.8^10 -5 .

What volume of 0.40 M NH3 solution must be added to 1Lof 0.1 m NH4Cl solution to give a buffer having pH of 10?For NH3, KB=1.8^10-5.

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What volume of 0.40 M NH₃ solution must be added to 1Lof 0.1 m NH₄Cl solution to give a buffer having pH of 10?For NH₃, K_B=1.8^10^-5.