Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
What volume of 0.40 M NH 3 solution must be added to 1Lof 0.1 m NH 4 Cl solution to give a buffer having pH of 10?For NH 3 , K B =1.8^10 -5 . What volume of 0.40 M NH3 solution must be added to 1Lof 0.1 m NH4Cl solution to give a buffer having pH of 10?For NH3, KB=1.8^10-5.
What volume of 0.40 M NH3 solution must be added to 1Lof 0.1 m NH4Cl solution to give a buffer having pH of 10?For NH3, KB=1.8^10-5.
[H+] = 10-10 [OH-] = Kw/H+ = 10-4 moles of NH4Cl = 0.1*1=0.1 for V Litre of NH3 ,moles of NH3 = 0.4*V now , Kb = [salt][OH-]/[base] 1.8*10-5 = (moles of salt )*10-4/(moles of base) moles of base(NH3) = 10/1.8*4=1.38L
[H+] = 10-10
[OH-] = Kw/H+ = 10-4
moles of NH4Cl = 0.1*1=0.1
for V Litre of NH3 ,moles of NH3 = 0.4*V
now ,
Kb = [salt][OH-]/[base]
1.8*10-5 = (moles of salt )*10-4/(moles of base)
moles of base(NH3) = 10/1.8*4=1.38L
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -