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The enthalpy of fusion of ice is 6kJ/mol. The heat capacity of water is 4.2j/g/K.What is the smallest amount of ice cubes at 0degrees,each containing i mole of water,that are needed to cool 500g of liquid water from 20 dgreess to 0degrees
Ans:7.Give me the complete solution
Dear student,
heat rejected by water = m*c*delT = 500*4.2*20
let m be the number of cubes
heat taken by cubes = m*6000
heat rejected = heat raken
=> m*6000 = 500*4.2*20
=> m = 7
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