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calcium carbonate reacts with azueous HCL to give cacl2 and co2 acoording to the reaction,caco3+2hcl--->cacl2+co2+h2o. what mass of caco3 is required to react completely with 25 ml of 0.75M hcl?
Dear Sundhar , M = moles /v ( litre ) moles HCL = 25 * .75/1000 = 0.0187 now, mole CaCO3 = moles HCL/2 = 0.0093 mass = moles * molar mass (CaCO3) Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Anil Pannikar IIT Bombay
Dear Sundhar ,
M = moles /v ( litre )
moles HCL = 25 * .75/1000 = 0.0187
now, mole CaCO3 = moles HCL/2 = 0.0093
mass = moles * molar mass (CaCO3)
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Anil Pannikar
IIT Bombay
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