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calcium carbonate reacts with azueous HCL to give cacl2 and co2 acoording to the reaction,caco3+2hcl--->cacl2+co2+h2o.
what mass of caco3 is required to react completely with 25 ml of 0.75M hcl?
Dear Sundhar ,
M = moles /v ( litre )
moles HCL = 25 * .75/1000 = 0.0187
now, mole CaCO3 = moles HCL/2 = 0.0093
mass = moles * molar mass (CaCO3)
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