How the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres?

Dear Chanchal,

  Mole = Volume/22.4 (At S.T.P or N.T.P.)

so according to this formula 1 Mole of gas occupies 22.4 litres at N.T.P.

 

suuppose diatomic gas is O2

 1 mole of O2 gas occupies  22.4 lit at N.T.P.

since O2 consist of two atoms means 1 mole of O2 contains 2 mole atom of oxygen.

thus we can say since 1 mole of O2 or 2 mole atoms of oxygen occupies = 22.4 litres at N.T.P.

therefore 1 mole atom of oxygen occupies = 22.4/2 = 11.2 litres at N.T.P.

 

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Its like that.

1 mole of diatomic gas at STP or NTP=22.4L

this means 2*(i mole of atom not molecule)=22.4

=> 1 mole atom(not molecule)=22.4/2

=11.2 litre.

Hello Student

We know that, 1 mole of gas occupies 22.4 L at NTP.
1 mole of diatomic gas (O₂) gas occupies 22.4 L at NTP
O₂ contains 2 moles of oxygen atom.
Hence 2 moles of oxygen atom occupies 22.4 L at NTP
Mole = Volume / 22.4
Therefore, 1 mole of oxygen atom contains 22.4 / 2 = 11.2 L at NTP.
Which means the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres.

I hope this answer will help you.