 # How the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres? ABHISHEK JAIN AskiitiansExpert-IITD
20 Points
11 years ago

Dear Chanchal,

Mole = Volume/22.4 (At S.T.P or N.T.P.)

so according to this formula 1 Mole of gas occupies 22.4 litres at N.T.P.

suuppose diatomic gas is O2

1 mole of O2 gas occupies  22.4 lit at N.T.P.

since O2 consist of two atoms means 1 mole of O2 contains 2 mole atom of oxygen.

thus we can say since 1 mole of O2 or 2 mole atoms of oxygen occupies = 22.4 litres at N.T.P.

therefore 1 mole atom of oxygen occupies = 22.4/2 = 11.2 litres at N.T.P.

ABHISHEK JAIN

11 years ago

Its like that.

1 mole of diatomic gas at STP or NTP=22.4L

this means 2*(i mole of atom not molecule)=22.4

=> 1 mole atom(not molecule)=22.4/2

=11.2 litre.

7 years ago
why one mole gas is having same volume at stp and ntp, both are not same temperatures. according to charles law, v is proportionl to volume.
7 years ago
why one mole gas is having same volume at stp and ntp, both are not same temperatures. according to charles law, v is proportionl to temperature
6 years ago
actually the volume at NTP and STP are not equal. at STP the volume of 1 mole of gas is 22.4 lt but at NTP the volume is 24.02 lt.  you can derive this from PV=nRT Yash Chourasiya
2 years ago
Hello Student

We know that, 1 mole of gas occupies 22.4 L at NTP.
1 mole of diatomic gas (O2) gas occupies 22.4 L at NTP
O2 contains 2 moles of oxygen atom.
Hence 2 moles of oxygen atom occupies 22.4 L at NTP
Mole = Volume / 22.4
Therefore, 1 mole of oxygen atom contains 22.4 / 2 = 11.2 L at NTP.
Which means the volume occupied by 1 mole atom of diatomic gas at NTP will be 11.2 litres.