# how to find hybridisation?i want shortcut or any trick

420 Points
13 years ago

Following is the way to find hybridisation

1st step    :  count the no. of valence electrons[ V ]
2nd step   :   now divide V by 8 ,if V >8
or
divide V by 2 ,if  V <=8                                   -[1]
if the remainder is still  not zero then
again divide it by 2,                                         - [2]
therefore the final value = quotient in 1+ quotient in 2
as    shown in the example
3rd step    :  compare the above obtained value with the table given below :-
sp          -   2
sp2        -   3
sp3        -   4
sp3d      -   5
sp3d2    -   6
sp3d3    -   7
ex:- for  c2h6
step  1   -   2[4 ] + 6[1] = 4+6=10
step  2    -   as 14>8
14/8, quotient=1  as remainder  = 6 which is not equal to zero
therefore 6 / 2   quotient=3
therefore final value=1+3=4
comparing with the table given above
the hybridisation is sp3.
note -  this is not applicable  to all compounds

All the best

AKASH GOYAL

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509 Points
13 years ago

you can use HON rule

according to this 2X=number of electrons in valence shell-charge+number of monovalent atoms attached(Cl,H etc)

if x comes 2 then hybridisation is sp

if 3 then sp2 ,if 4 then sp3 and so on

example ..hybridisation of NH4+

2x=5+4-1

x=4 so hybridisation is sp3

approve my ans if u like

Devasish Bindani
45 Points
13 years ago

to find the hybridisation of an element in a given compound  first count the number of σ bonds and the no. of lone pairs present then it becomes the steric no of the element then just get the hybridisation. hybridisation forsteric no.

2--sp

3--sp2

4--sp3

5--sp3d

6--sp3d2

7--sp3d3

thats it the short cut count the no of σ bonds  and ya got the hybridisation

note:- its applicable to all compounds provided ya know the structure or no of atoms connected to the given atom whose hybridisation is to be found hers an example check out

here no of σ bettween Cr and O are 5 there fore the hybridisation is sp3d

note sigma bond are the primary bonds so whereever you see double bond then there are one sigma and one pi bonds

for lone pair take NH3 nitrogen has 1 lone pair and 3 σ bonds thus the hybridisation is sp3

aishwarya aishu
18 Points
11 years ago

can u please tell me how to find out the hybridisation for ph3 please and aso give me the explanation thank you

Rahul John Joseph
31 Points
10 years ago
Just count the no.of sigma bonds and lone pairs (if any) Thats all!
siddharth singhal
19 Points
10 years ago
What is the hybridization of I 3 minus?
saksham agrawal
14 Points
10 years ago
for any compound identify the central atom then count the no. of sigma bonds and no. of lone pairs on it and then add them. eg: in a CO2 molecule carbon is the central atom, no. of sigma bonds are 2 and no. of lone pairs are 0 then sum is 2 which means sp hybridization is there.
Aazim Bill SE Yaswant
20 Points
10 years ago
for a shortcut. find the no of atoms attached to it. then write its corresponding hybridisation. if central atom is attached to 2.. sp.. 3..sp2.. so on
Parveen Khurana
31 Points
10 years ago
Countcount the no. Of sigma bond and no of lone of atom whose hybridisation is to be predicted . All single bonds ate sigma , in amultiple bond one will sigma others be pie
ashu
34 Points
10 years ago
Accr to VSEPR theory H={V+M-C+A} the simplest method V = valence electrons in central atom M=number of univalent atom attached to central atom C=charge on cation A=charge on anion
harit
14 Points
9 years ago
dont,t get confused just no. of sigma bond + lone pairs ,if sum is

2--sp

3--sp2

4--sp3

5--sp3d

6--sp3d2

7--sp3d3

Yashwardhan Bahure
24 Points
8 years ago
but what if remainder is not zero. it wont be divisible by 2 ex. CH3
anurag
15 Points
8 years ago
hybridization of h3po3

soliha noor
53 Points
8 years ago
calculate no. of bond pairs[sigma bonds only] and lone pairs and add them..the no. u get is the hybridisation of that atom...if h=2=sp,,if h=3=sp2,,if h=4=sp3,,if h=5=sp3d and so on
Nike Puma
24 Points
7 years ago
I hav a formula for finding hybridisationI call it "Magic Number"So......Magic Number = Number of connections +1/2 ( Group no. of central atom - Valency of central atom ± Charge on molecule)**# Note that -ve charge is added and +ve charge is subtractedAlso that this doesn`t apply for complexesSo group 13 group 4Now compare the magic no. with2--sp3--sp24--sp35--sp3d6--sp3d27--sp3d3 Eg.) For H3O+Magic Number = 3 + 1/2( 6 - 3 - 1 ) = 3 + 1/2( 2 ) = 3 + 1 = 4Now 4 corresponds to sp3 hybridHence H3O+ is sp3 hybridised group 3 group 14
Ashish Nayakidi
36 Points
7 years ago
You can calculate accordingly as
H={V+M-(C+A)}
V=valency of the central metal atom
M=no. of monovalent atoms attached to the central metal atom
C=charge on cation
A=charge on anion
3 years ago
Dear student,

To find the Hybridisation, you have to first identify the Central atom, then on that central atom find the sum of lone pairs and the total number of sigma bonds connecting the central atom with other atoms (You have to keep in mind that all single bonds are sigma bonds, but if double or triple bond is there, then only one out of those bonds is sigma, rest are all pi bonds).
The number you obtained should be the representative to the hybridisation. If sum is
2 → sp
3 → sp2
4 → sp3
5 → sp3d
6 → sp3d2
7 → sp3d3

Hope it helps.
Thanks and regards,
Kushagra