Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Dear Pradeep
Following is the way to find hybridisation
1st step : count the no. of valence electrons[ V ]2nd step : now divide V by 8 ,if V >8 or divide V by 2 ,if V <=8 -[1] if the remainder is still not zero then again divide it by 2, - [2] therefore the final value = quotient in 1+ quotient in 2 as shown in the example3rd step : compare the above obtained value with the table given below :- sp - 2 sp2 - 3 sp3 - 4 sp3d - 5 sp3d2 - 6 sp3d3 - 7ex:- for c2h6step 1 - 2[4 ] + 6[1] = 4+6=10step 2 - as 14>8 14/8, quotient=1 as remainder = 6 which is not equal to zero therefore 6 / 2 quotient=3 therefore final value=1+3=4 comparing with the table given above the hybridisation is sp3.note - this is not applicable to all compounds
All the bestAKASH GOYALAskiitiansExpert-IITDPlease feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
you can use HON rule
according to this 2X=number of electrons in valence shell-charge+number of monovalent atoms attached(Cl,H etc)
if x comes 2 then hybridisation is sp
if 3 then sp2 ,if 4 then sp3 and so on
example ..hybridisation of NH4+
2x=5+4-1
x=4 so hybridisation is sp3
approve my ans if u like
to find the hybridisation of an element in a given compound first count the number of σ bonds and the no. of lone pairs present then it becomes the steric no of the element then just get the hybridisation. hybridisation forsteric no.
2--sp
3--sp2
4--sp3
5--sp3d
6--sp3d2
7--sp3d3
thats it the short cut count the no of σ bonds and ya got the hybridisation
note:- its applicable to all compounds provided ya know the structure or no of atoms connected to the given atom whose hybridisation is to be found hers an example check out
here no of σ bettween Cr and O are 5 there fore the hybridisation is sp3d
note sigma bond are the primary bonds so whereever you see double bond then there are one sigma and one pi bonds
for lone pair take NH3 nitrogen has 1 lone pair and 3 σ bonds thus the hybridisation is sp3
can u please tell me how to find out the hybridisation for ph3 please and aso give me the explanation thank you
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !