For a p-electron, orbital angular moment is

(A) √2h (B) h

(C) √6h (D) 2h plz EXPLAIN IT PROPER....

O.A.M= SQRT[ l*(l+1)]   * h

FOR P ELECTRON  L VALUE IS 1.

THEREFORE O.A.M= SQRT(2) * h             

THEREFORE OPTION---A

orbital angular momentum of an orbital is given by {l(l+1)}^1/2  h

for p orbital, l=1          (s=0

                                 p=1

                                 d=2

                                 f=3)

o angular momentum= {1(1+1)}^1/2 h ={1*2}^1/2   h  = 2^1/2 h

so the answer is A under root pf 2 multiplied by h