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An electron in a hydrogen atom in its ground state absorsbs twice its ionisation energy. What is the wavelength of the emitted electcron ?
The ionisation energy of hydrogen is 21. 72 x 10-19 J
So, energy supplied to the electron is 2x 21.72 x 10-19 J. To knock the electron out of atom, it needs 21.72 x 10-19 J. The remaining energy of 21.72 x 10-19J appear as kinetic energy.
K.E = 1/2 mv2 or 2 K.E = mv2 or v = (2K.E / m)1/2
Wave length = h / mv
Wave length = h / (2 K.E. m)1 = 1 x 10-19 m
Formula is -13.6Z2/N2 EV/atom
Use this to find ionisation energy (as it is equal to total energy)
Then use E= hc/λ
You will get the answer.
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