For CrCl3.xNH3 ,elevation in boiling point of one molal solution is triple of one molal aqueous soln of urea. Assuming 100% ionization of complex molecule, calculate the value of x.

For the elevation in boiling point to be 3 times that of urea, the solution of complex should contain 3 times more number of particles compared to urea solution.

[Cr(NH₃)₄Cl] Cl₂ can give 3 times more particles than Urea because, Complex ion is 1 particle, 2 Cl^1- particles are obtained after ionisation as they are present out side the sphere of coordination. So, X= 4.

3 particles should be; 1 complex ion + 2 ions, invariably Cl^1- . So, Coordination number 6 is satisfied by 4 NH₃ and 2 Cl^1-