Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The difference between heats of reaction at constant pressure and constant volume for the reaction 2C 6 H 6 (I) + 150 2 (g) " 12CO 2 (g) + 6H 2 O (I) at 25 ? C in kJ mol -1 is 1) -7.43 2) +3.72 3) -3.72 4) +7.43



The difference between heats of reaction at constant pressure and constant volume for the reaction


2C6H6 (I) + 1502(g) "12CO2 (g) + 6H2O (I)


at 25?C in kJ mol-1 is




1)


 -7.43 





2)


 +3.72





3)


-3.72    





4)


+7.43




Grade:12

2 Answers

Askiitians Expert Sahil Arora - IITD
19 Points
11 years ago

Dear Student,

Heat of reaction at constant pressure is ΔH and at constant volume is ΔU.

ΔH-ΔU=ΔngRT

Δng=12-15=-3

ΔngRT=(-3)*(8.314*10-3KJ/mol/K)*(298 K)=-7.43

one more thing,someone may think of dividing the reaction by 2..but that will be wrong.

On multiplying by a factor,ΔH and ΔU also get multiplied by the factor..

All the best Pratik !!!




Regards,

Askiitians Experts

Sahil Arora
Saurabh Kumawat
31 Points
3 years ago
2C6H6(l)+15O2(g) -> 12CO2(g)+6H2O(l) at 25℃ in KJ/mol
∆H-∆U=∆ngRT
∆ng=12-15=-3
∆ngRT=(-3)×(8.314×10^-3KJ/mol/K)×298=-7.43

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free