Ionisation potential and electron affinity of fluorine are 17.42 and 3.45 eV respectively. Calculate the electronegativeity of fluorine.

Dear Sakshi,

According to Mulliken equation:

        X = (I.P+E.A)/5.6  when both IP and EA are taken in eV.

        X_F = (17.42+3.45)5.6  = 3.726

 Thus Electronegativity of Flourine is 3.726

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