Grade 10Physical Chemistry
16 g of an ideal gas SOx occupies 5.6L.at STP.The value of x is
16 g of an ideal gas SOx occupies 5.6L.at STP.The value of x is
4 Answers
sree lakshmi
since it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6
=64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2
the molecule is SO2
[mass of sulpher =32g
mass of oxygen atom =16g]
adilakshmigogada 27
since it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6
=64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2
the molecule is SO2
[mass of sulpher =32g
mass of oxygen atom =16g
Parv Joshi
ince it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6
=64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2
the molecule is SO2
[mass of sulpher =32g
mass of oxygen atom =16g]
irshad hussain
5.6 l is occupied by 16 g of gas
22.4 l is occupied by (16/5.6) × 22.4 g = 64 g
Gram molecular mass = 64 g
Now mass of SOx= 32+ 16x
ATP
32 + 16x= 64
16x = 32
x = 2
The gas is SO2
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