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Grade: 10

                        

16 g of an ideal gas SOx occupies 5.6L.at STP.The value of x is

3 months ago

Answers : (3)

sree lakshmi
73 Points
							
since it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6 
                                  =64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2 
the molecule is SO
[mass of sulpher =32g 
mass of oxygen atom =16g]
3 months ago
adilakshmigogada 27
101 Points
							
 
since it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6 
                                  =64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2 
the molecule is SO
[mass of sulpher =32g 
mass of oxygen atom =16g
17 days ago
Parv Joshi
100 Points
							
 
ince it is an ideal gas the volume of 1 mol gas is 22.4L
mass of 5.6L gas is 16g(given)
then the mass 22.4 L =(22.4×16)/5.6 
                                  =64g
the mass of SOx is 64g
ie 32+x16=64
x16=32
x=2 
the molecule is SO
[mass of sulpher =32g 
mass of oxygen atom =16g]
15 days ago
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