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```
16 g of an ideal gas SOx occupies 5.6L.at STP.The value of x is

```
3 months ago

```							since it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6                                   =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g]
```
3 months ago
```							 since it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6                                   =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g
```
17 days ago
```							 ince it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6                                   =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g]
```
15 days ago
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