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16 g of an ideal gas SOx occupies 5.6L.at STP.The value of x is
since it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6 =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g]
since it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6 =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g
ince it is an ideal gas the volume of 1 mol gas is 22.4Lmass of 5.6L gas is 16g(given)then the mass 22.4 L =(22.4×16)/5.6 =64gthe mass of SOx is 64gie 32+x16=64x16=32x=2 the molecule is SO2 [mass of sulpher =32g mass of oxygen atom =16g]
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