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100ml of PH3 when decomposed produced phosporous and hydrogen. The change in volume is
The equation for the decomposition is: 4PH3 (g) = P4 (s)+ 6H2 (g) (Elemental phosphorus exists as tetraatomic molecules).When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).Hence, 100 ml of PH3 will yield 150 ml of H2.Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).There is a 50% increase in volume.
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