Grade 11Physical Chemistry
100 ml of 0.8M Naoh are used to neutralise 100 ml solution obtained by passing 2.7g So2Cl2 in water ,
100 ml of 0.8M Naoh are used to neutralise 100 ml solution obtained by passing 2.7g So2Cl2 in water ,
1 Answer
varun
HELLO,
Understand this reaction first,
=> SO2Cl2 + 2H2O ---------------> H2SO4 + 2HCl
H2SO4 + 2NaOH --------------> Na2SO4 + 2H2O
2HCl + 2NaOH ----------------> 2NaCl + 2H2O
from the above reaction we can predict that,
both 1 mole H2SO4 requires 2 moles of NaOH
and
2 mole of HCl requires 2 moles of NaOH
therefore,
total moles of NaOH is
=> 0.1 X 0.8
= 0.08 moles
in which 0.04 is used by each H2SO4 and HCl
because H2SO4 we use twice the mole of NaOH
therefore,
Molarity of H2SO4 = 0.02/0.1
= 0.2 M
Molarity of HCl = 0.04/0.1
= 0.4M
THANK YOU
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