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1021 molecules are removed from 280 mg carbon mono oxide . Calculate the no of moles of carbon mono oxide

Ritik , 6 Years ago
Grade 11
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

initial mole of CO = 0.280/28 = 0.01 mole
removed mole = 1021/(6.022*1023) = 0.001661
SO remaining mole of CO = 0.01 – 0.001661 = 0.00834 mole.
Hope it clears. If you like answer then please aprove it.

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