 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        1 mole of nitrogen gas 0.8Atm takes 38 seconds to diffuse through a pinhole where is 1 mole of unknown compound of Xenon with fluorine at 1.6 ATM takes 56.26 second to diffuse through the small one then the molecular formula of the compound is`
one year ago

```							We know that for compounds with molecular mass M1 and M2, diffusion rate r1 and r2 at pressure P1 and P2 respectively, can be written as  r1/r2 = (P1/P2)(M2/M1)1/2and also r1/r2 = t2/t1where t1 and t2 are time taken by the gas to diffuse.  (P1/P2)(M2/M1)1/2 = t2/t1 Let 1st compound be nitrogen gas then M1 = mass of 1mole of nitrogen gas = 28grams                                                               P1 = 0.8atm                                                                t1 = 38sLet 2nd compound be the mixture of xenon and fluorine with M2 = M                                                                                                P2 = 1.6atm                                                                                                 t2 = 56.26s Then,                     (0.8/1.6)(M/14)1/2 = 56.26/38                          (M/14)1/2 = 2.96                                      M = 245.5gramsMass of 1 mole of the compound = 245.5 gramsMass of 1 molecule of the compound = 245.5uMass of 1 atom of Xe = 131.5uMass of two atoms of Xe = 263u > 245.5u Two or more atom of Xe is not possible in given compound that means compound have 1 atom of Xe.Let n atoms of fluorine present in the compounds then,(mass of 1 atom of Xe) + n(mass of 1 atom of F) = 245.5                                                 131.5 + 19n = 245.5                                                                  n = 6  Thew compound is XeF6
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions