MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
1 mole of nitrogen gas 0.8Atm takes 38 seconds to diffuse through a pinhole where is 1 mole of unknown compound of Xenon with fluorine at 1.6 ATM takes 56.26 second to diffuse through the small one then the molecular formula of the compound is
17 days ago

Answers : (1)

Kapil Khare
59 Points
							
We know that for compounds with molecular mass M1 and M2, diffusion rate r1 and r2 at pressure P1 and P2 respectively, can be written as 
 
r1/r2 = (P1/P2)(M2/M1)1/2
and also r1/r2 = t2/t1
where t1 and t2 are time taken by the gas to diffuse.
 
\implies (P1/P2)(M2/M1)1/2 = t2/t1
 
Let 1st compound be nitrogen gas then M1 = mass of 1mole of nitrogen gas = 28grams
                                                               P1 = 0.8atm
                                                                t1 = 38s
Let 2nd compound be the mixture of xenon and fluorine with M2 = M
                                                                                                P2 = 1.6atm
                                                                                                 t2 = 56.26s
 Then,
                     (0.8/1.6)(M/14)1/2 = 56.26/38
\implies                          (M/14)1/2 = 2.96
\implies                                      M = 245.5grams
Mass of 1 mole of the compound = 245.5 grams
Mass of 1 molecule of the compound = 245.5u
Mass of 1 atom of Xe = 131.5u
Mass of two atoms of Xe = 263u > 245.5u
\implies Two or more atom of Xe is not possible in given compound that means compound have 1 atom of Xe.
Let n atoms of fluorine present in the compounds then,
(mass of 1 atom of Xe) + n(mass of 1 atom of F) = 245.5
\implies                                                 131.5 + 19n = 245.5
\implies                                                                  n = 6
 
\implies Thew compound is XeF6
 
17 days ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 276 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details