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Grade 12th passPhysical Chemistry

1 mole of n2o4 get dissiciated 50% at 1 bar pressure and 298k temperatur calculate gibbir fru energy
please give me a solution

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Profile image of honeykumar
6 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
6 Years ago
N2O4 → 2NO2
moles of unreacted N2O4 = 1 (1 - 0.2) = 0.8
moles of NO2 = 2 * 0.2 = 0.4
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total moles n2 = 0.8 + 0.4 = 1.2
P1/(T1 n1) = P2/(T2 * n2)
1/(300 * 1) = P2/(600 * 1.2)
P2 = 2.4 atm