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Physical Chemistry

1 mole of n2 and 2 moles of h2 are allowed to react and to attain the following equlibria in 1litre vessel n2 +3h2=2nh3 .what is the value of kc if the heat capacity of constant pressure of gas mixture decrease by 11r/3 at equilibrium.

Profile image of Rupak Sharma
7 Years agoGrade
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1 Answer

Profile image of Arun
6 Years ago
Initial mole ratio N2:H2 is 1:3
At equilibrium, 50% of N2, H2 has reacted and equilibrium pressure is P
2
​ 
 +3H 
2
​ 
 →2NH 
3
​ 
 
y3y2y
At equilibrium, 50% of each reactant reacted, the number of moles will become half.
The mole of N2=y− 
2
y
​ 
 
The moles of H2=3y− 
2
3y
​ 
 
THE moles of NH3= 
2
2y
​ 
 
Total moles at equilibrium= 
2
y
​ 
 + 
2
3y
​ 
 + 
2
2y
​ 
 =3y
Partial pressure of H2= 
Totalmoles
MolesofH2
​ 
 ×Totalpressure= 
2
3y
​ 
 × 
3y
1
​ 
 ×P= 
2
P
​