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`        1.2 g of mg is burnt in a closed vessel which contains 0.5 g of o2. millimeters of 0.5 m h2so4 required to dissolve the residue in the vessel is?`
2 years ago

suvra bhattacharjee
13 Points
```							The equation is as follows:2Mg + O2  ------>  2MgO(s)      (g)                (s)Therefore 2 moles of Mg require 1 mole of O2 to produce 2 moles of MgO.Calculate actual moles.moles= mass/ molar massMg=    1/24  = 0.041667O2=   0.56/32 = 0.0175MgO=Mole ratio of Mg: O2   = 2:1find mass of Mg that reacts:that means 2 mole of Mg reacts with 1 moles of O2If 1 = 2 Then 0.0175 = 0.0175 x 2                     =0.035 moles of magnesiummass of magnesium that reacts:mass= moles x molar mass        = 24 x 0.035                       0.84 gThat means that of the 1 gram of magnesium that reacts only 0.84 grams is usedTherefore magnesium is in excess and by 0.16
```
one year ago
Sheeba Roohi
15 Points
```							Eq. Of Mg = 1.2÷12=0.1Eq. Of O² = 0.5÷8 = 0.0625Therefore Eq. Of MgO = 0.0625Eq. Of mg left = 0.1-0.0625=0.0375Eq. Of H²SO⁴=0.0375+0.0625=0.1Vol. of H²SO⁴ = 0.1÷0.25×2=0.2L =200mL
```
one year ago
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