Grade 11Physical Chemistry0.75 mole isothermally 27 k from 15 l to 25 l the maximum work is Sabugarrafiya 8 Years agoGrade 11
Arun8 Years ago Dear student w = –n R T ln (V2/V1) w = – 2.303 * nRT log (V2/V1) w = –2.303 * 0.75 * 8.314 * 27 log (25/15) on solvingw = –85.995 Joules RegardsArun (askIITians forum expert)