0.3 g of an organic compound containing C, H and O on combustion yields 0.44 g of CO2 and 0.18 g of H20, with two O atoms per molecule. Find the empirical formula of compound.

Question

Bhavya · Answer

Dear student
You should first find % of C, H and O
% of C = (12/44) * (wt of CO2/wt of organic compound) * 100
% of H = (2/18)* (wt of H2O/wt of organic compound) * 100
% of O = 100 – % of C – % of H
Then apply empirical formula method to find it.

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0.3 g of an organic compound containing C, H and O on combustion yields 0.44 g of CO2 and 0.18 g of H20, with two O atoms per molecule. Find the empirical formula of compound.

0.3 g of an organic compound containing C, H and O on combustion yields 0.44 g of CO2 and 0.18 g of H20, with two O atoms per molecule. Find the empirical formula of compound.

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0.3 g of an organic compound containing C, H and O on combustion yields 0.44 g of CO2 and 0.18 g of H20, with two O atoms per molecule. Find the empirical formula of compound.

0.3 g of an organic compound containing C, H and O on combustion yields 0.44 g of CO2 and 0.18 g of H20, with two O atoms per molecule. Find the empirical formula of compound.

1 Answers

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