Grade 11Physical Chemistry
Balance the following redox reactions by ion-electron method
Balance the following redox reactions by ion-electron method
3 Answers
Vishi
Reduction half -
MnO4- --> Mn2+
MnO4- --> Mn2+ + 4H2O
MnO4- + 8H+ --> Mn2+ + 4H2O
MnO4- + 8H+ + 5e --> Mn2+ + 4H2O
2MnO4- + 16H+ + 10e --> 2Mn2+ + 8H2O
Oxidation half -
SO2 --> HSO4-
SO2 + 2H2O --> HSO4-
SO2 + 2H2O --> HSO4- + 3H+
SO2 + 2H2O --> HSO4- + 3H+ + 2e
5SO2 + 10H2O --> 5HSO4- + 15H+ + 10e
Adding both eq ,
2MnO4- + 16H+ + 10e + 5SO2 + 10H2O -----> 2Mn2+ + 8H2O + 5HSO4- + 15H+ + 10e
2MnO4- + H+ + 5SO2 + 2H2O -----> 2Mn2+ + 5HSO4-
Isra Abass
Reduction half -
MnO4- --> Mn2+
MnO4- --> Mn2+ + 4H2O
MnO4- + 8H+ --> Mn2+ + 4H2O
MnO4- + 8H+ + 5e --> Mn2+ + 4H2O
2MnO4- + 16H+ + 10e --> 2Mn2+ + 8H2O
Oxidation half -
SO2 --> HSO4-
SO2 + 2H2O --> HSO4-
SO2 + 2H2O --> HSO4- + 3H+
SO2 + 2H2O --> HSO4- + 3H+ + 2e
5SO2 + 10H2O --> 5HSO4- + 15H+ + 10e
Adding both eq ,
2MnO4- + 16H+ + 10e + 5SO2 + 10H2O -----> 2Mn2+ + 8H2O + 5HSO4- + 15H+ + 10e
2MnO4- + H+ + 5SO2 + 2H2O -----> 2Mn2+ + 5HSO4-
Isra Abass
Manganese goes from oxidation state +7 to +2. A 5-electron change and a reduction.
Sulfur goes from an oxidation state of +4 to +6. A 2-electron change and an oxidation.
5e- + MnO4- = Mn2+
SO2 = HSO4- + 2e-
Balance the charge with H+
8 H+ + 5e- + MnO4- = Mn2+
SO2 = HSO4- + 2e- + 3 H+
Now balance the H using H2O
If done correctly, the O should be balanced
Multiply each half reaction by a number that will give the same number of electrons in each—in this case TEN electrons and then add the two half reactions.
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