question is attached in image whose ANSWER IS 5.IT IS A SINGLE INTEGER VALUE TYPE QUESTION
AVANISH KUMAR GUPTA , 6 Years ago
Grade 12th Pass
Physical Chemistry> question is attached in image whose ANSWE...
1 AnswersArun
Last Activity: 6 Years ago
Suppose runner and cyclist reach at same position in time t, and the observer has travelled x distance in this time
Speed of runner= 15 km/h=25/6 m/s
speed of cyclist=25 km/h = 125/18 m/s
Time t = distance travelled/speed
t = (20-x)/(25/6) = (30-x)/(125/18)
x=5m
putting in eqn to get t= 18/5
Speed of observer to travel 5 meter distance in 18/5 sec= >
5/v=18/5 =>v=25/18 m/s =5 km/h
Speed of runner= 15 km/h=25/6 m/s
speed of cyclist=25 km/h = 125/18 m/s
Time t = distance travelled/speed
t = (20-x)/(25/6) = (30-x)/(125/18)
x=5m
putting in eqn to get t= 18/5
Speed of observer to travel 5 meter distance in 18/5 sec= >
5/v=18/5 =>v=25/18 m/s =5 km/h
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