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please answer
consider a particle initially moving with a velocity of 5 m s-1 starts deceleratig at the constant rate of 2 m s-2.
find the distance travelled in the third second.

Purva Agrawal , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

 
V=U+AT
Since v=0, we substitute values.
0=5-2t(because it is decelerating and hence it is negative).
T=2.5s
Displacement in nth second is given as
Sn=u+a(2n-1)/2
For displacement in second second, we get S=5-1(3)=12
For displacement in third second, we get S=5-1(5)=20.

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