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The value ofπ/2∫((cos 3x+1)/(2 cos x -1)) dx, is 0A) 2B) 1C) 1/2D) 0

Technical GURUJI , 6 Years ago
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anser 1 Answers
Aditya Gupta

Last Activity: 6 Years ago

cos3x= 4c^3-3c, where c is cosx
So we have to integrate
(4c^3-3c+1)/(2c-1)= 2c^2+c-1= cosx+cos2x
We can easily integrate this from 0 to pi/2 to obtain the final answer as 1.

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