Please solve the question in the attachment ....... ......... ....
Pawan joshi , 6 Years ago
Grade 12th pass
Integral Calculus> Please solve the question in the attachme...
1 Answers
Aditya Gupta
Last Activity: 6 Years ago
divide both numerator and denom by x^2 to get
(3x^2 – 1/x^2)/(1+1/x+x^3)^2
now put 1+1/x+x^3=y
so that dy/dx= 3x^2 – 1/x^2
so, the integral becomes 1/y^2
we get – 1/y
= – 1/(1+1/x+x^3) + C
= –x/(x^4+x+1)+C
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