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Grade: 12th pass
        
Please solve the question in the attachment ....... ......... .... 
one year ago

Answers : (1)

Aditya Gupta
1717 Points
							
divide both numerator and denom by x^2 to get
(3x^2 – 1/x^2)/(1+1/x+x^3)^2
now put 1+1/x+x^3=y
so that dy/dx= 3x^2 – 1/x^2
so, the integral becomes 1/y^2
we get  – 1/y
= – 1/(1+1/x+x^3) + C
= –x/(x^4+x+1)+C
one year ago
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