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please help me to solve this attached prob..............

please help me to solve this attached prob..............

Question Image
Grade:12

1 Answers

Krishanu Das
26 Points
4 years ago
write sec as 1/cosx.multiply numerator and denominator by cosx and then 2u will get 2cosx/sin2x+2write 2 cosx = sinx+ cosx - (sinx-cos x)separate like this a+b/c=a/c+b/c where a=sinx+cosx,b=sinx-cosx c=sin2x+2then take c below a as = (sinx-cosx)^2-3and below b as (sinx+cosx)^2+1then i think u can integrate by urself

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