please help me to solve this attached prob..............

write sec as 1/cosx.multiply numerator and denominator by cosx and then 2u will get 2cosx/sin2x+2write 2 cosx = sinx+ cosx - (sinx-cos x)separate like this a+b/c=a/c+b/c where a=sinx+cosx,b=sinx-cosx c=sin2x+2then take c below a as = (sinx-cosx)^2-3and below b as (sinx+cosx)^2+1then i think u can integrate by urself