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Grade: 12th Pass
        
 
Lt x−2
 
2x+2-16
4x-16 
pls evaluate the limit tommorow is my exam
 
one year ago

Answers : (1)

Arun
22987 Points
							
Dear Ashwin
this is 0/0 form.
now you can put L’hospital rule here.
lt(x--->2)  2x+2 * ln2 / 4x ln4
lt(x--->2)  2x+2 * ln2 / 4x * 2 *ln2
lt(x--->2)  2x * 22/2* 4x   
now put limit
4 *4 / 2 * 16
 = ½
Regards
Arun 
one year ago
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