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Lt x−2 2x+2-164x-16 pls evaluate the limit tommorow is my exam

ASh , 7 Years ago
Grade 12th Pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Ashwin
this is 0/0 form.
now you can put L’hospital rule here.
lt(x--->2)  2x+2 * ln2 / 4x ln4
lt(x--->2)  2x+2 * ln2 / 4x * 2 *ln2
lt(x--->2)  2x * 22/2* 4x   
now put limit
4 *4 / 2 * 16
 = ½
Regards
Arun 

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